1896 Canadian federal election

1896 Canadian federal election

← 1891 June 23, 1896 1900 →
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213 seats in the House of Commons 107 seats needed for a majority
Turnout	62.9%[1] (1.5pp)
First party Second party   Leader Wilfrid Laurier Charles Tupper Party Liberal Conservative Leader since 1887 1896 Leader's seat Quebec East[a] Cape Breton Last election 90 seats, 45.2% 117 seats, 48.6% Seats won 117 86 Seat change 27 31 Popular vote 401,425 467,415 Percentage 41.4% 48.2% Swing 3.8% 0.4%
1896 Canadian electoral map
The Canadian parliament after the 1896 election
Prime Minister before election Charles Tupper Conservative Prime Minister after election Wilfrid Laurier Liberal

The 1896 Canadian federal election was held on June 23, 1896, to elect members of the House of Commons of Canada of the 8th Parliament of Canada. Though the Conservative Party, led by Prime Minister Charles Tupper, won a plurality of the popular vote, the Liberal Party, led by Wilfrid Laurier, won the majority of seats (with only 41 percent of the vote) to form the next government. The election ended 18 years of Conservative rule.

This was first election in Canada to produce a House of Commons with elected members of four parties. The Liberals and Conservative shared the chamber with elected members of the farmer-based Patrons of Industry and McCarthyites.

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