1940 United States presidential election in Utah

1940 United States presidential election in Utah
Roosevelt 50–60% 60–70%	Willkie 50-60% 60-70%
President before election; Franklin D. Roosevelt; Democratic	Elected President ; Franklin D. Roosevelt; Democratic

The 1940 United States presidential election in Utah took place on November 5, 1940 as part of the 1940 United States presidential election. All contemporary forty-eight states took part, and state voters selected four voters to the Electoral College, who voted for president and vice president.

Utah, like every other state west of the Continental Divide, voted for Franklin D. Roosevelt over Wendell Willkie by a substantial margin. This was the first time any Democrat won the state more than twice. Roosevelt landslided Utah with 62.25 percent of the vote. The percentage, however, wasn’t as large as his victory in the state four years earlier. As of the 2020 presidential election^[update], this is the last election in which Piute County voted for a Democratic presidential candidate.^[1]

^ Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016

[how-1] Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016

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1940 United States presidential election in Utah

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