1988 United States presidential election in Alabama

1988 United States presidential election in Alabama
Bush 40–50% 50–60% 60–70% 70–80%	Dukakis 40–50% 50–60% 60–70% 70–80% 80–90%
President before election; Ronald Reagan; Republican	Elected President ; George H. W. Bush; Republican

The 1988 United States presidential election in Alabama took place on November 8, 1988. All fifty states, and the District of Columbia, were part of the 1988 presidential election. Alabama voters chose nine electors to the Electoral College, which selected the president and vice president. Alabama was won by incumbent United States Vice President George H. W. Bush of Texas, who was running against Massachusetts Governor Michael Dukakis. Bush ran with Indiana Senator Dan Quayle as Vice President, and Dukakis ran with Texas Senator Lloyd Bentsen.

The vast majority of counties in Alabama voted for Bush, with the major exception being the Black Belt, which with its predominantly African-American populace voted overwhelmingly Democratic. Macon County had been the most Democratic in the nation in 1980 and 1984, and it was Dukakis’ sixth-best county in the nation with a margin of over four-to-one for the Massachusetts Governor.^[1]

^ "1988 Presidential Election Statistics". Dave Leip’s U.S. Election Atlas.

[1] "1988 Presidential Election Statistics". Dave Leip’s U.S. Election Atlas.

[1]

1988 United States presidential election in Alabama

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