The presidential election of 1988 was a very partisan election for Washington, with 98.5% of the electorate voting for either the Democratic or Republican parties.[1] In typical form for the time and political climate in Washington – an East/West split can be seen in the voter turnout: with the coastal counties voting in the majority for Dukakis, and the inland counties voting mainly for Bush.
Dukakis carried Washington state with 50.05% of the vote to Bush's 48.46%, a margin of 1.59%, making it the closest state in the election. This made Washington one of ten states (along with the District of Columbia) to vote for Dukakis, even as Bush won a convincing victory nationally. Washington weighed in for this election as over 9% more Democratic than the national average. For decades prior to 1988, Washington had been a swing state, and it had gone Republican in the four preceding elections, even voting for losing Republican candidate Gerald Ford in 1976. But the state's strong Democratic tilt in 1988 portended the political direction the state would take in the modern era. Dukakis’ 1988 victory began a Democratic winning streak in Washington state that has never been broken since. Washington's Democratic trend was largely driven by the dramatic shift toward the Democrats among urban and suburban voters that began in the 1980s. While Bush won many rural counties, Dukakis won the two most heavily populated counties in Washington state: King County and Pierce County.