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| Turnout | 72.6% (of registered voters) 57.7% (of voting age population) | |||||||||||||||||||||||||
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 County Results
Bush 50-60% 60-70% 70-80% 80-90%
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| Elections in Utah |
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The 2004 United States presidential election in Utah took place on November 2, 2004. It was part of the 2004 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.
Utah was won by incumbent President George W. Bush by a 45.5% margin of victory. Prior to the election, all leading news organizations considered this a state Bush would win, or otherwise considered as a safe red state. It is a strongly Republican state and has supported the party's nominee in every presidential election since 1968. With 71.54 percent of the popular vote, Utah was Bush's strongest state in the 2004 election.[1]
This was the first of four instances in which a presidential candidate gained over 70% of a state's vote after Ronald Reagan's 1984 landslide. The others are Mitt Romney in Utah in 2012 and Barack Obama in Hawaii in 2008 and 2012. These last three all involved a candidate with a close tie to the state: Barack Obama was born in Hawaii, and Mitt Romney, as the first Mormon on a major-party presidential ticket, was popular in Mormon-majority Utah and would later represent the state in the United States Senate.
- ^ "2004 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.