Ferdinand, Idaho

Ferdinand, Idaho
Location of Ferdinand in Idaho County, Idaho.
Location of Ferdinand in Idaho County, Idaho.
Coordinates: 46°09′07″N 116°23′24″W / 46.15194°N 116.39000°W / 46.15194; -116.39000
CountryUnited States
StateIdaho
CountyIdaho
Area
 • Total
0.17 sq mi (0.45 km2)
 • Land0.17 sq mi (0.45 km2)
 • Water0.00 sq mi (0.00 km2)
Elevation3,727 ft (1,136 m)
Population
 • Total
159
 • Density925.71/sq mi (358.13/km2)
Time zoneUTC-8 (Pacific (PST))
 • Summer (DST)UTC-7 (PDT)
ZIP code
83526
Area code208
FIPS code16-27460
GNIS feature ID2410495[2]

Ferdinand is a city in Idaho County, Idaho, United States. The population was 159 at the 2010 census, up from 145 in 2000. At the southern end of the Nez Perce Indian Reservation, it was founded by F.M. Bieker shortly after the reservation was opened for settlement in 1895. It was named after Ferdinand, Indiana, where his mother's family had lived.[4]

Historical population
CensusPop.Note
1920255
1930196−23.1%
194022313.8%
1950206−7.6%
1960176−14.6%
1970157−10.8%
1980144−8.3%
1990135−6.2%
20001457.4%
20101599.7%
2019 (est.)162[5]1.9%
U.S. Decennial Census[6]
  1. ^ "2019 U.S. Gazetteer Files". United States Census Bureau. Retrieved July 9, 2020.
  2. ^ a b U.S. Geological Survey Geographic Names Information System: Ferdinand, Idaho
  3. ^ Cite error: The named reference wwwcensusgov was invoked but never defined (see the help page).
  4. ^ "Lost map set stage for location of Ferdinand". Lewiston Morning Tribune. October 6, 1955. p. 6-LCSE.
  5. ^ "Population and Housing Unit Estimates". United States Census Bureau. May 24, 2020. Retrieved May 27, 2020.
  6. ^ "Census of Population and Housing". Census.gov. Retrieved June 4, 2015.

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